Special Segments In Triangles

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Introduction to triangles:
A triangle is one of the basic shapes of geometry: a polygon with three corners or vertices and three sides or edges which are line segments.  In an equilateral triangle all sides have the same length. An equilateral triangle is also a regular polygon with all angles measuring 60°. In an isosceles triangle, two sides are equal in length. (Source: Wikipedia)
Special Segments in Triangles

The following are the special segments in triangles:
Perpendicular bisector
Median
Altitude
Angle bisector

Perpendicular bisector
Segment to passes during the middle point of a face of a triangle and is also vertical to that face. Perpendicular bisectors perform not for all time exceed during the opposed vertex.
Median
Special segments to join a vertex of a triangle toward the middle points of the opposite face. Each triangle contains three medians.

Altitude
Special segments specifically vertical to a face of a triangle, and it interconnect with the vertex opposite to face. Mainly altitudes rise as of the bottom and their length is too ...
... the height of the triangle, except either face can contain an altitude.

Angle bisector
Special segment of a triangle to bisect an angle of the triangle also subsequently interconnect the opposed face of the triangle.

Examples for Triangles
Example 1
Compute the area of an triangles through a base of 16 inches also a height of 5 inches.
Solution
Area of the triangle A = `1/2 b h`
Base of the triangle = 16 inches
Height of the triangle = 5 inches
Area of the triangle = `1/2` x 16 x 5
= 1/2 xx 80

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Area of the triangle = 40 in2
Example 2
Compute the area of an  triangle through a base of 25 cm inches also a height of 10 cm inches.
Solution
Area of the triangle A = `1/2 b h`
Base of the triangle = 25 cm
Height of the triangle = 10 cm
Area of the triangle = `1/2` x 25 x 10
= 1/2 xx 250

Area of the triangle = 125 cm^2
Example 3
Compute the area of an  triangle through a base of 30 m inches also a height of 15 m inches.
Solution
Area of the triangle A = 1/2 b h
Base of the triangle = 30 m
Height of the triangle = 15 m
Area of the triangle = 1/2` x 30 x 15
= 1/2 xx 450
Area of the triangle = 225 m2

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